Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Review: 110

Answer

$x = -\dfrac{42}{23}$

Work Step by Step

$\log_6{x}-\log_6(4x+7) = 1$ $\log_6\bigg(\dfrac{x}{4x+7}\bigg) = 1$ $6^{\log_6\big(\frac{x}{4x+7}\big)} = 6^1$ $\dfrac{x}{4x+7} = 6$ $x=6(4x+7)$ $x=24x+42$ $23x = -42$ $x = -\dfrac{42}{23}$
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