Answer
$x = -\dfrac{42}{23}$
Work Step by Step
$\log_6{x}-\log_6(4x+7) = 1$
$\log_6\bigg(\dfrac{x}{4x+7}\bigg) = 1$
$6^{\log_6\big(\frac{x}{4x+7}\big)} = 6^1$
$\dfrac{x}{4x+7} = 6$
$x=6(4x+7)$
$x=24x+42$
$23x = -42$
$x = -\dfrac{42}{23}$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 12 - Review - Page 908: 110
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