## Algebra: A Combined Approach (4th Edition)

Published by Pearson

# Chapter 12 - Review: 105

#### Answer

{$-1,4$}

#### Work Step by Step

Step 1: $\log_{4} (x^{2}-3x)=1$ Step 2: $(x^{2}-3x)=4^{1}$ Step 3: $(x^{2}-3x)=4$ Step 4: $x^{2}-3x-4=0$ Step 5: $x^{2}+1x-4x-4=0$ Step 6: $x(x+1)-4(x+1)=8$ Step 7: $(x+1)(x-4)=0$ Step 8: $x=-1$ or $x=4$ Therefore, the solution set is {$-1,4$}.

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