Answer
b) upward with the vertex at $(-\frac{1}{2}, \frac{1}{2})$
Work Step by Step
$f(x) = 5(x+\frac{1}{2})^2+\frac{1}{2}$
The graph opens upward due to no negative sign being the coefficient on the $5$. Also, the function has its vertex at $x=\frac{-1}{2}$.
