Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Section 11.5 - Quadratic Functions and Their Graphs - Exercise Set - Page 812: 56

Answer

Please see the graph. The red graph is the original function. The blue graph is the function $y=f(x-1)+1$.

Work Step by Step

The graph of $f(x)$ has the points as follows: $(-5, -2)$, $(-4, -1)$, $(-3, 0)$, $(-2, 1)$, $(-1, .5)$, $(0,0)$, $(1,1)$, $(2,2)$, $(3,3)$, $(4,4)$, $(5,5)$ For the function $y=f(x-1)+1$, we shift the graph of $f(x)$ to the left one unit and up one unit. Thus, the function $y=f(x-1)+1$ has the following points: $(-5, -2)$, $(-4, -1)$, $(-3, 0)$, $(-2, 1)$, $(-1, 2)$, $(0,1.5)$, $(1,1)$, $(2,2)$, $(3,3)$, $(4,4)$, $(5,5)$
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