Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Section 11.5 - Quadratic Functions and Their Graphs - Exercise Set - Page 812: 54

Answer

Please see the graph. The red graph is the original function, and the blue graph is the function $y=f(x+3)$.

Work Step by Step

The graph of $f(x)$ has the points as follows: $(-5, -2)$, $(-4, -1)$, $(-3, 0)$, $(-2, 1)$, $(-1, .5)$, $(0,0)$, $(1,1)$, $(2,2)$, $(3,3)$, $(4,4)$, $(5,5)$ For the function $y=f(x+3)$, we shift the graph of $f(x)$ to the right three units. This means the function $y=f(x+3)$ has the following points: $(-5, 1)$, $(-4, .5)$, $(-3, 0)$, $(-2, 1)$, $(-1, 2)$, $(0,3)$, $(1,4)$, $(2,5)$, $(3,6)$, $(4,7)$, and $(5,8)$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.