Answer
X-intercepts are $(-1,0)$ and $(5,0)$
Y-intercept is $(0, -5)$
Vertex is $(2, -9)$
Work Step by Step
$f(x)=x^2-4x-5$
$f(x)=(x-5)(x+1)$
$0=(x-5)(x+1)$
$x-5=0$
$x=5$
$x+1=0$
$x=-1$
x-intercepts are $-1, 5$
y-intercept:
$f(x)=x^2-4x-5$
$f(0)=0^2-4*0-5$
$f(0)=0-0-5$
$f(0)=-5$
Vertex:
$f(x)=x^2-4x-5$
$y=x^2-4x-5$
$y+5=x^2-4x$
$y+5+(1/2*-4)^2=x^2-4x+(1/2*-4)^2$
$y+5+(-2)^2=x^2-4x+(-2)^2$
$y+5+4=x^2-4x+4$
$y+9=(x-2)^2$
$y=(x-2)^2-9$
Vertex of $(2,-9)$
