Answer
$\sqrt 13$
Work Step by Step
$a = 1, b=-3, c=-1$
$\sqrt {b^2-4ac}$
=$ \sqrt {(-3)^2 - (4\times1\times-1)}$
=$\sqrt {9-(-4)}$
=$\sqrt {9+4}$
=$\sqrt 13$
=$\sqrt 13$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 11 - Section 11.1 - Solving Quadratic Equations by Completing the Square - Exercise Set - Page 766: 86
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
