Chapter 11 - Section 11.1 - Solving Quadratic Equations by Completing the Square - Exercise Set: 84

$2\sqrt{7}$

Work Step by Step

Given $a = 1, b = 6, c = 2$ we have $\sqrt{b^2-4ac} = \sqrt{6^2-4 \times 1 \times 2} = \sqrt{36-8} = \sqrt{28} = \sqrt{4 \times 7} = \sqrt{2^2 \times 7} = 2\sqrt{7}$

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