Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Section 11.1 - Solving Quadratic Equations by Completing the Square - Exercise Set: 77


The length of equal legs of the isosceles triangle is 14.14 centimeter.

Work Step by Step

We will use Pythagoras theorem to find out the length of each leg. By Pythagoras theorem, $P^2+B^2=H^2$ Where, P= Perpendicular B= Base H= Hypotenuse Here $P=B=x$ and $H=20$ Step-1: Substituting in the formula, $x^2+x^2=20^2$ $2x^2=400$ Step 2: Dividing both sides by 20 $x^2=\frac{400}{2}$ $x^2=200$ Step-3: Using the square root property $x=±\sqrt200$ $x=±14.1421$ Since the leg of isosceles triangle cannot be negative, the length is approximately 14.14 centimeters.
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