Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Section 11.1 - Solving Quadratic Equations by Completing the Square - Exercise Set - Page 766: 83

Answer

$2\sqrt 6$

Work Step by Step

$a = 2, b=4, c=-1$ $\sqrt {b^2-4ac}$ =$ \sqrt {4^2 - (4\times2\times-1)}$ =$\sqrt {16-(-8)}$ =$\sqrt {16+8}$ =$\sqrt 24$ =$\sqrt {4\times6}$ =$\sqrt{ 2^2\times6}$ =$2\sqrt 6$
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