#### Answer

$-a^{6}b^{3}$

#### Work Step by Step

$\sqrt[3] {-a^{18}b^{9}}$
=$(-a^{18}b^{9})^{\frac{1}{3}}$
=$(-1)^{\frac{1}{3}}\times (a^{18})^{\frac{1}{3}}\times (b^{9})^{\frac{1}{3}}$
=$(-1)\times (a^{6})\times (b^{3})$
=$-a^{6}b^{3}$

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

$-a^{6}b^{3}$

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