Answer
$\sqrt {6}+\sqrt 2-4\sqrt 3-4$
Work Step by Step
$(\sqrt 2-4)(\sqrt 3+1)$
=$\sqrt 2(\sqrt 3+1)-4(\sqrt 3+1)$
=$\sqrt 2\sqrt 3+\sqrt 2-4\sqrt 3-4$
=$\sqrt {2\times3}+\sqrt 2-4\sqrt 3-4$
=$\sqrt {6}+\sqrt 2-4\sqrt 3-4$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 10 - Test - Page 750: 18
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