Answer
$\frac{4x^{2}}{9}$
Work Step by Step
$(\frac{8x^{3}}{27})^{\frac{2}{3}}$=$(\frac{2^{3}\times x^{3}}{3^{3}})^{\frac{2}{3}}$=$(\frac{2^{2}\times x^{2}}{3^{2}})$=$\frac{4x^{2}}{9}$
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