#### Answer

$\frac{4x^{2}}{9}$

#### Work Step by Step

$(\frac{8x^{3}}{27})^{\frac{2}{3}}$=$(\frac{2^{3}\times x^{3}}{3^{3}})^{\frac{2}{3}}$=$(\frac{2^{2}\times x^{2}}{3^{2}})$=$\frac{4x^{2}}{9}$

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

$\frac{4x^{2}}{9}$

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