Answer
$3b^{3}$
Work Step by Step
$\sqrt[4] {81b^{12}}$
=$\sqrt[4] {81\times b^{12}}$
=$\sqrt[4] {81} \times \sqrt[4] {b^{12}}$
=$\sqrt[4] {(3)^{4}} \times (b^{12})^{\frac{1}{4}}$
=$3\times b^{3}$
=$3b^{3}$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 10 - Section 10.5 - Integrated Review - Radicals and Rational Exponents - Page 720: 8
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