Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.5 - Integrated Review - Radicals and Rational Exponents - Page 720: 24

Answer

$-2b^{2}\sqrt[5] {2}$

Work Step by Step

Step 1: $\sqrt[5] {-64b^{10}}$ Step 2: $\sqrt[5] {-64}\times \sqrt[5] {b^{10}}$ Step 3: $\sqrt[5] {-32\times 2}\times \sqrt[5] {b^{10}}$ Step 4: $\sqrt[5] {(-2)^{5}}\times \sqrt[5] {2}\times (b^{10})^{\frac{1}{5}}$ Step 5: $-2\times \sqrt[5] {2}\times b^{2}$ Step 6: $-2\times b^{2} \times\sqrt[5] {2}$ Step 7: $-2b^{2} \times\sqrt[5] {2}$ Step 8: $-2b^{2}\sqrt[5] {2}$
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