Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.5 - Integrated Review - Radicals and Rational Exponents: 14

Answer

$16x^{\frac{1}{2}}$

Work Step by Step

$\frac{(2x^{\frac{1}{3}})^{4}}{x^{\frac{5}{6}}}$ =$\frac{(2)^{4}\times(x^{\frac{1}{3}})^{4}}{x^{\frac{5}{6}}}$ =$\frac{16\times x^{\frac{4}{3}}}{x^{\frac{5}{6}}}$ =$16\times (x)^{\frac{4}{3}-\frac{5}{6}}$ =$16\times (x)^{\frac{4(2)-5}{6}}$ =$16\times (x)^{\frac{8-5}{6}}$ =$16\times (x)^{\frac{3}{6}}$ =$16x^{\frac{1}{2}}$
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