Answer
$16x^{\frac{1}{2}}$
Work Step by Step
$\frac{(2x^{\frac{1}{3}})^{4}}{x^{\frac{5}{6}}}$
=$\frac{(2)^{4}\times(x^{\frac{1}{3}})^{4}}{x^{\frac{5}{6}}}$
=$\frac{16\times x^{\frac{4}{3}}}{x^{\frac{5}{6}}}$
=$16\times (x)^{\frac{4}{3}-\frac{5}{6}}$
=$16\times (x)^{\frac{4(2)-5}{6}}$
=$16\times (x)^{\frac{8-5}{6}}$
=$16\times (x)^{\frac{3}{6}}$
=$16x^{\frac{1}{2}}$
