Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.5 - Integrated Review - Radicals and Rational Exponents: 7

Answer

$-2y$

Work Step by Step

$\sqrt[5] {-32y^{5}}$ =$\sqrt[5] {-32\times y^{5}}$ =$\sqrt[5] {-32} \times \sqrt[5] {y^{5}}$ =$\sqrt[5] {(-2)^{5}} \times \sqrt[5] {y^{5}}$ =$-2\times y$ =$-2y$
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