Answer
$$(n-4)(n+2)$$
Work Step by Step
Factor
$$n^{2}−2n-8.$$
Find numbers that are factors of $-8$ and sum to $-2$:
$$(-4)(2)=-8;\space -4+2=-2.$$
The polynomial is a product of two binomials:
$$n^{2}−2n-8=(n-4)(n+2).$$
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