Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Skills Handbook - Factoring and Operations with Polynomials - Exercises - Page 979: 8



Work Step by Step

Factor $$n^{2}−2n-8.$$ Find numbers that are factors of $-8$ and sum to $-2$: $$(-4)(2)=-8;\space -4+2=-2.$$ The polynomial is a product of two binomials: $$n^{2}−2n-8=(n-4)(n+2).$$
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