Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Skills Handbook - Factoring and Operations with Polynomials - Exercises - Page 979: 7



Work Step by Step

Factor $$a^{2}-8a+12.:$$ Find numbers that are factors of $12$ and sum to $-8$ $$(-6)(-2)=12;\space -6-2=-8.$$ The polynomial is a product of two binomials: $$a^{2}-8a+12=(a-6)(a-2).$$
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