#### Answer

$$2x(x^{2}+2x-4)$$

#### Work Step by Step

Factor $$2x^{3}+4x^{2}-8x.$$
Factor each term:
$$2x^{3}=2\times x\times x\times x$$
$$4x^{2}=2\times 2\times x\times x$$
$$-8x=-2\times 2\times 2\times x.$$
The common factors are $2$ and $x$, so factor those out:
$$2x^{3}+4x^{2}-8x=2x(x^{2}+2x-4).$$