## Algebra 2 Common Core

$$2x(x^{2}+2x-4)$$
Factor $$2x^{3}+4x^{2}-8x.$$ Factor each term: $$2x^{3}=2\times x\times x\times x$$ $$4x^{2}=2\times 2\times x\times x$$ $$-8x=-2\times 2\times 2\times x.$$ The common factors are $2$ and $x$, so factor those out: $$2x^{3}+4x^{2}-8x=2x(x^{2}+2x-4).$$