Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Skills Handbook - Factoring and Operations with Polynomials - Exercises: 13

Answer

$$2x(x^{2}+2x-4)$$

Work Step by Step

Factor $$2x^{3}+4x^{2}-8x.$$ Factor each term: $$2x^{3}=2\times x\times x\times x$$ $$4x^{2}=2\times 2\times x\times x$$ $$-8x=-2\times 2\times 2\times x.$$ The common factors are $2$ and $x$, so factor those out: $$2x^{3}+4x^{2}-8x=2x(x^{2}+2x-4).$$
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