Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Skills Handbook - Factoring and Operations with Polynomials - Exercises: 14

Answer

$$(y-5)^{2}$$

Work Step by Step

Factor $$y^{2}−10y+25.$$ Find numbers that are factors of $25$ and sum to $-10$: $$(-5)(-5)=25;\space -5-5=-10.$$ The polynomial is a product of two binomials: $$y^{2}−10y+25=(y-5)(y-5)=(y-5)^{2}.$$
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