Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 9 - Sequences and Series - Chapter Review - Page 604: 9

Answer

$a_1 = 20$ $a_2 = 10$ $a_3 = 5$ $a_4 = \frac{5}{2}$ $a_5 = \frac{5}{4}$

Work Step by Step

In this exercise, we are given a recursive formula, which relates one term to the term before it. We are given the initial term $a_1 = 20$, so we need to come up with the next four terms of the sequence, $a_2$ through $a_5$: For $n = 2$: $a_2 = \frac{1}{2}a_{2 - 1}$ Simplify: $a_2 = \frac{1}{2}a_{1}$ Substitute $a_1 = 20$ into the formula: $a_2 = \frac{1}{2}(20)$ Multiply first: $a_2 = \frac{20}{2}$ Simplify the fraction: $a_2 = 10$ For $n = 3$: $a_3 = \frac{1}{2}a_{3 - 1}$ Simplify: $a_3 = \frac{1}{2}a_{2}$ Substitute $a_2 = 10$ into the formula: $a_3 = \frac{1}{2}(10)$ Multiply first: $a_3 = \frac{10}{2}$ Simplify the fraction: $a_3 = 5$ For $n = 4$: $a_4 = \frac{1}{2}a_{4 - 1}$ Simplify: $a_4 = \frac{1}{2}a_{3}$ Substitute $a_3 = 5$ into the formula: $a_4 = \frac{1}{2}(5)$ Multiply: $a_4 = \frac{5}{2}$ For $n = 5$: $a_5 = \frac{1}{2}a_{5 - 1}$ Simplify: $a_5 = \frac{1}{2}a_{4}$ Substitute $a_4 = \frac{5}{2}$ into the formula: $a_5 = \frac{1}{2}(\frac{5}{2})$ Multiply: $a_5 = \frac{5}{4}$
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