Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 9 - Sequences and Series - Chapter Review - Page 604: 15

Answer

This is an arithmetic sequence. The common difference $d$ is $15$. $a_32 = 468$

Work Step by Step

Let's look at the terms to see if we can find a pattern: $a _2 - a_1 = 18 - 3 = 15$ $a_3 - a_2 = 33 - 18 = 15$ $a_4 - a_3 = 48 - 33= 15$ This is an arithmetic sequence because the same number is added to the previous term to get the next term, which means there is a common difference, and that difference $d$ is $15$. We can find the 32nd term by figuring out the explicit formula of a sequence, which will give us the exact term we are looking for. Use the explicit formula for arithmetic sequences, which is $a_n = a_1 + (n - 1)d$, where $a_1$ is the first term of the sequence and $d$ is the common difference; in this exercise, $a_1$ is $3$ and $d$ is $15$: $a_n = 3 + (n - 1)(15)$ Substitute $32$ for $n$ to find the $32$nd term of the sequence: $a_32 = 3 + (32 - 1)(15)$ Evaluate what's in parentheses first: $a_32 = 3 + (31)(15)$ Then multiply: $a_32 = 3 + 465$ Add to solve: $a_32 = 468$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.