Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 9 - Sequences and Series - Chapter Review - Page 604: 7

Answer

$a_1 = 1$ $a_2 = 0$ $a_3 = -3$ $a_4 = -8$ $a_5 = -15$

Work Step by Step

Substitute numbers $1$ through $5$ to find the first five terms of this series: For $n = 1$: $a_1 = -(1)^2 + 2(1)$ Evaluate exponents first, according to order of operations: $a_1 = -1 + 2(1)$ Multiply next: $a_1 = -1 + 2$ Add to simplify: $a_1 = 1$ For $n = 2$: $a_2 = -(2)^2 + 2(2)$ Evaluate exponents first, according to order of operations: $a_2 = -4 + 2(2)$ Multiply next: $a_2 = -4 + 4$ Add to simplify: $a_2 = 0$ For $n = 3$: $a_3 = -(3)^2 + 2(3)$ Evaluate exponents first, according to order of operations: $a_3 = -9 + 2(3)$ Multiply next: $a_3 = -9 + 6$ Add to simplify: $a_3 = -3$ For $n = 4$: $a_4 = -(4)^2 + 2(4)$ Evaluate exponents first, according to order of operations: $a_4 = -16 + 2(4)$ Multiply next: $a_4 = -16 + 8$ Add to simplify: $a_4 = -8$ For $n = 5$: $a_5 = -(5)^2 + 2(5)$ Evaluate exponents first, according to order of operations: $a_5 = -25 + 2(5)$ Multiply next: $a_5 = -25 + 10$ Add to simplify: $a_5 = -15$
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