Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 9 - Sequences and Series - Chapter Review - Page 604: 8

Answer

$a_1 = 2$ $a_2 = 3$ $a_3 = 5$ $a_4 = 9$ $a_5 = 17$

Work Step by Step

In this exercise, we are given a recursive formula, which relates one term to the term before it. We are given the initial term $a_1 = 2$, so we need to come up with the next four terms of the sequence, $a_2$ through $a_5$: For $n = 2$: $a_2 = 2a_{2 - 1} - 1$ Simplify: $a_2 = 2a_{1} - 1$ Substitute $a_1 = 1$ into the formula: $a_2 = 2(2) - 1$ Multiply first: $a_2 = 4 - 1$ Subtract: $a_2 = 3$ For $n = 3$: $a_3 = 2a_{3 - 1} - 1$ Simplify: $a_3 = 2a_{2} - 1$ Substitute $a_2 = 3$ into the formula: $a_3 = 2(3) - 1$ Multiply first: $a_3 = 6 - 1$ Subtract: $a_3 = 5$ For $n = 4$: $a_4 = 2a_{4 - 1} - 1$ Simplify: $a_4 = 2a_{3} - 1$ Substitute $a_3 = 5$ into the formula: $a_4 = 2(5) - 1$ Multiply first: $a_4 = 10 - 1$ Subtract: $a_4 = 9$ For $n = 5$: $a_5 = 2a_{5 - 1} - 1$ Simplify: $a_5 = 2a_{4} - 1$ Substitute $a_4 = 9$ into the formula: $a_5 = 2(9) - 1$ Multiply first: $a_5 = 18 - 1$ Subtract: $a_5 = 17$
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