Answer
$x = 49$
Work Step by Step
First, isolate the radical on one side of the equation by adding $3$ to both sides of the equation:
$\sqrt{x}-3+3=4+3\\
\sqrt {x} = 7$
Square both sides of the equation to get rid of the radical:
$(\sqrt{x})^2=7^2\\
x = 7^{2}$
$x = 49$
To check for extraneous solutions, substitute $49$ for $x$ into the original equation:
$\sqrt {49} - 3 = 4$
Evaluate the radical term first:
$7 - 3 = 4$
$4 = 4$
Both sides of the equation equal one another; therefore, the answer is correct. There are no extraneous solutions.
