Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 8 - Rational Functions - 8-4 Rational Expressions - Practice and Problem-Solving Exercises - Page 533: 59

Answer

$\dfrac{3}{2}$

Work Step by Step

Rewrite the radical as an exponential expression: $\log_5 {\left(5 \cdot 5^{\frac{1}{2}}\right)}$ If two exponential expressions having the same base are multiplied together, add the exponents, keeping the base as-is: $=\log_5 {5^{\frac{3}{2}}}$ Let $y=\log_5{5^{\frac{3}{2}}}$. Use the definition of logarithm $\log_b {x} = y \longleftrightarrow b^{y} = x$ to write an exponential equation. In this exercise, the base $b$ is $5$, $y$ is the exponent, and $x$ is $5^{\frac{3}{2}}$: $5^{y} = 5^{\frac{3}{2}}$ If two numbers having the same base are equal, that means that their exponents are also the same, so set the exponents equal to one another to solve for $y$: $y = \frac{3}{2}$ Thus, $\log_5{5\sqrt5}=\log_5{\left(5^{\frac{3}{2}}\right)}=\frac{3}{2}$.
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