Answer
There are no vertical asymptotes for this function.
There is a hole at $x = 3$ on the graph.
Work Step by Step
To find the vertical asymptote, find the zeros of the denominator by setting each factor equal to zero and solving:
$x - 3 = 0$
$x = 3$
We have a vertical asymptote at $x = 3$ only if it is not a zero of the numerator. In this exercise, $x = 3$ is also a zero of the numerator; therefore, it is not a vertical asymptote of this function. This also means that $x = 3$ is a removable discontinuity or hole that can be removed by filling in a single point.
