Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 7 - Exponential and Logarithmic Functions - Chapter Review - Page 490: 69

Answer

$x=1+\ln{16}\approx 3.7726$

Work Step by Step

\begin{align*} e^{x-1}&=16 &\text{Divide 4 to both sides.}\\\\ \ln{e^{x-1}}&=\ln{16} &\text{Take the natural logarithm of both sides.}\\\\ (x-1)(\ln{e})&=\ln{16}&\text{Power Property of Logarithms.}\\\\ (x-1)(1)&=\ln{16}&\text{Note that $\ln{e}=1$.}\\\\ x-1&=\ln{16}\\\\ x&=1+\ln{16}&\text{Add 1 to both sides.}\\\\ x&\approx 3.7726\end{align*} Check: \begin{align*} 4e^{1+\ln{16}-1}&\stackrel{?}=64\\\\ 4(16)&\stackrel{\checkmark}=64\end{align*} Thus, the solution is $x=1+\ln{16}\approx 3.7726$.
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