Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 7 - Exponential and Logarithmic Functions - Chapter Review - Page 490: 52

Answer

$x=0.75$

Work Step by Step

\begin{align*} \log{\left(25^{2x}\right)}&=\log{125} &\text{Take the common logarithm of both sides.}\\\\ 2x\cdot \log{25} &=\log{125} &\text{Apply the Power Property of Logarithms.}\\\\ \dfrac{2x\cdot\log{25}}{2\log{25}}&=\dfrac{\log{125}}{2\log{25}} &\text{Divide $2\log{25}$ to both sides.}\\\\ x&= \dfrac{\log{125}}{2\log{25}}\\\\ x&=0.75 &\text{Use a calculator to evaluate.} \end{align*}
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