Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 7 - Exponential and Logarithmic Functions - 7-5 Exponential and Logarithmic Equations - Practice and Problem-Solving Exercises - Page 473: 40

Answer

$x=3\cdot10^8=300,000,000$

Work Step by Step

Recall the quotient property of logarithms (pg. 462): $\log_b{\frac{m}{n}}=\log_b{m}-\log_b{n}$ Applying this property to our equation, we get: $\log_{10}{\frac{x}{3}}=8$ Next, recall the definition of a logarithm (pg. 451): $\log_{b}{x}=y$ iff $b^y=x$ Applying this definition to our equation (with $b=10, y=8, x=x/3$), we get: $10^{8}=\frac{x}{3}$ $x=3\cdot 10^8$ $x=300,000,000$ We confirm that the answer works: $\log (3\cdot 10^8)-\log 3=8$ $\log \frac{3\cdot10^8}{3}=8$ $\log 10^8=8$ $8=8$
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