Answer
$2$
Work Step by Step
Recall the product property of logarithms (pg. 462):
$\log_b{mn}=\log_b{m}+\log_b{n}$
We apply this property to our equation:
$\log_6{12}+\log_6{3}\\
=\log_6{(12\cdot 3)}\\
=\log_6{36}\\
=\log_6{6^2}$
Next, recall the power property of logarithms (pg. 462):
$\log_b{m^n}=n\log_b{m}$
We use this property to simplify our last expression:
$\log_6{6^2}\\
=2\log_6{6}\\
=2\times 1\\
=2$
We used the fact that $\log_{6}{6}=1$ (because $6^1=6$).
