Answer
$\log_3$ ${7}$ + $2$ $\log_3$ ${(2x - 3)}$
Work Step by Step
Use the Product Property of Logarithms. According to this property, $\log_b$ ${mn}$ = $\log_b$ ${m}$ + $\log_b$ ${n}$. Thus, the given expression is equivalent to:
$\log_3$ ${7}$ + $\log_3$ ${(2x - 3)^{2}}$
Use the Power Property of Logarithms to rewrite this expression. The property states that $\log_b$ ${m^n}$ = $n$ $\log_b$ ${m}$. Thus, the expression above is equivalent to:
$\log_3$ ${7}$ + $2$ $\log_3$ ${(2x - 3)}$
