Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 7 - Exponential and Logarithmic Functions - 7-4 Properties of Logarithms - Practice and Problem-Solving Exercises - Page 466: 38

Answer

$pH=12$

Work Step by Step

The formula for the pH of a substance, as a function of hydrogen ion concentration ($H^{+}$) is (pg. 465): $pH=-\log_{10}[H^{+}]$ Applying this to our case ($H^{+}=10^{-12}$), we get: $pH=-\log_{10}[H^{+}]=-\log_{10}{10^{-12}}=-(-12)\log_{10}{10}=12$ Here we used the power property of logarithms (pg. 462): $\log_b{m^n}=n\log_b{m}$ We also used the fact that $\log_{10}{10}=1$ (because $10^1=10$).
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.