Answer
$2x^5 \sqrt[4] {x^2}$
Work Step by Step
Use the rule \sqrt[m]{a}\cdot \sqrt[m]{b}=\sqrt[m]{ab}$, where a,b>0$, to obtain:
$=\sqrt[4] {16 \cdot x^{8} \cdot x^{14}}$
Simplify:
$=\sqrt[4] {16 \cdot x^{22}}$
Factor the radicand so that we can take the fourth roots later:
$=\sqrt[4] {2^4 \cdot x^{20} cdot x^{2}}$
$=\sqrt[4] {2^4 \cdot (x^{5})^4 \cdot x^{2}}$
Take the fourth roots:
$=2x^5 \sqrt[4] {x^2}$
