Answer
$0.2x^2y$
Work Step by Step
In this exercise, $0.008$ is a perfect cube, $y^3$ is a perfect cube, and $x^6$ is also a perfect cube. Take the cube roots of $0.008$, $y^3$, and $x^6$:
$=\sqrt[3]{0.2^2y^3(y^2)^3}\\
=0.2yx^2\\
=0.2x^2y$