Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - Mid-Chapter Quiz - Page 389: 10

Answer

$\dfrac{2}{x}$

Work Step by Step

Rewrite the radicand as a product of bases raised to the $2^{nd}$ power so that we can take them out from under the radical sign. Since we are working with a fraction in this problem, we will use this step for both the numerator and the denominator: $=\dfrac{\sqrt {(6)^2(x^2)^2}}{\sqrt {(3)^2(x^3)^2}}$ Take the square root of everything that is raised to the power of $2$ from under the radical sign, then simplify: $=\dfrac{6x^2}{3x^3}$ $=\dfrac{2x^2}{x^3}$ $=\dfrac{2x^2}{x^2(x)}$ Cancel the common facto $x^2$ to obtain: $=\dfrac{2}{x}$
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