Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - Chapter Test - Page 427: 8

Answer

$6\sqrt {7xz}$

Work Step by Step

In this problem, we just add the coefficients together and keep the radical as-is because the radicals are the same for both terms: $4\sqrt {7xz} + 2\sqrt {7xz}$ = $(4+2)\sqrt {7xz}=6\sqrt{7xz}$
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