Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - Chapter Test - Page 427: 19

Answer

$-f(x) \cdot g(x) = -x^3 + 5x^2 - 8x + 4$ $\text{The domain is all real numbers.}$

Work Step by Step

In this problem, we are asked to multiply two functions. Let us go ahead and set up the multiplication problem, separating the two functions with parentheses: $-f(x) \cdot g(x) = -(x - 2)(x^2 - 3x + 2)$ Let's distribute the $-$ sign to each of the terms in the binomial to get: $-f(x) \cdot g(x) = (-x + 2)(x^2 - 3x + 2)$ Multiply each term in the binomial with each term in the trinomial: $-f(x) \cdot g(x) = (-x)(x^2) + (2)(x^2) + (-3x)(-x) + (-3x)(2) + (2)(-x) + (2)(2)$ Multiply out, to simplify: $-f(x) \cdot g(x) = -x^3 + 2x^2 + 3x^2 - 6x - 2x + 4$ Group like terms: $-f(x) \cdot g(x) = -x^3 + (2x^2 + 3x^2) + (-6x - 2x) + 4$ Combine like terms: $-f(x) \cdot g(x) = -x^3 + 5x^2 - 8x + 4$ There are no restrictions on $x$. The domain is the set of all real numbers since there are no values of $x$ that will make the function undefined.
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