Answer
$7x^2\sqrt {2}$
Work Step by Step
When we multiply two radicals, we make sure the indices are the same. Then we can multiply the coefficients together and then the radicands together as well. In this case, the indices are the same, so we multiply:
$\sqrt {(7)(14)(x^3)(x) }$
Multiply to simplify:
$\sqrt {(98)(x^4)}$
We can break down the number $98$ into its constituents: $49$, a perfect square, and $2$:
$\sqrt {(49)(2)(x^4)}$
Let's now rewrite the radicand as a product of bases raised to the $2nd$ power so that we can take them out from under the radical sign:
$\sqrt {((7)^2)(2)(x^2)^2}$
Now, we can take the square roots of everything that is raised to the power of $2$ from under the radical sign:
$7x^2\sqrt {2}$
