Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - Chapter Test - Page 427: 13

Answer

$-x^2\sqrt {2x}$

Work Step by Step

Before we can subtract these two numbers, we must transform them so that the radicands are the same. Only then can we perform the operation we are asked to do. Let's expand the radicands in all of the radicals so that they are rewritten as the product of a perfect square and another number: $\sqrt {8x^5} - \sqrt {18x^5}$ = $\sqrt {4 \cdot 2 \cdot x^4 \cdot x} - \sqrt {9 \cdot 2 \cdot x^4 \cdot x}$ We can now take the square roots of all the perfect squares: $2x^2\sqrt {2x} - 3x^2\sqrt {2x}$ Subtract the coefficients, keeping the base as-is: $-x^2\sqrt {2x}$
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