Answer
$\dfrac{5\sqrt[4] {x^3} + x}{x}$
Work Step by Step
To get rid of radicals in the denominator, multiply both numerator and denominator by a factor that will make the radical in the denominator an integer. In this exercise, that factor would be $\sqrt[4] {x^3}$:
$\dfrac{5 + \sqrt[4] {x}}{\sqrt[4] {x}} \cdot \dfrac{\sqrt[4] {x^3}}{\sqrt[4] {x^3}}$
Use distributive property:
$=\dfrac{5\sqrt[4] {x^3} + \sqrt[4] {x^4}}{\sqrt[4] {x^4}}$
Simplify radicals:
$=\dfrac{5\sqrt[4] {x^3} + x}{x}$
