Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-3 Binomial Radical Expressions - Practice and Problem-Solving Exercises - Page 379: 60

Answer

$2$

Work Step by Step

To get rid of radicals in the denominator, multiply both numerator and denominator by the conjugate of the denominator: $\dfrac{\sqrt {2} + \sqrt {6}}{\sqrt {1.5} + \sqrt {0.5}} \cdot \dfrac{\sqrt {1.5} - \sqrt {0.5}}{\sqrt {1.5} - \sqrt {0.5}}$ Use the FOIL method to expand the numerator and denominator: $\dfrac{(\sqrt {2})(\sqrt {1.5}) - (\sqrt {2})(\sqrt {0.5}) + (\sqrt {6})(\sqrt {1.5}) - (\sqrt {6})(\sqrt {0.5})}{(\sqrt {1.5})(\sqrt {1.5}) - (\sqrt {1.5})(\sqrt {0.5}) + (\sqrt {0.5})(\sqrt {1.5}) - (\sqrt {0.5})(\sqrt {0.5})}$ Multiply to simplify: $\dfrac{(\sqrt {3}) - (\sqrt {1}) + (\sqrt {9}) - (\sqrt {3})}{(\sqrt {2.25}) - (\sqrt {0.75}) + (\sqrt {0.75}) - (\sqrt {0.25})}$ Simplify radicals: $\dfrac{-1 + 3}{1.5 - 0.5}$ Combine like terms: $\dfrac{2}{1}=2$
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