Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-3 Binomial Radical Expressions - Lesson Check - Page 378: 7

Answer

$-16-3\sqrt{2}$

Work Step by Step

Using the FOIL Method which is given by $(a+b)(c+d)=ac+ad+bc+bd,$ the given expression, $ (2+3\sqrt{2})(1-3\sqrt{2}) ,$ is equivalent to \begin{align*} & 2(1)+2(-3\sqrt{2})+3\sqrt{2}(1)+3\sqrt{2}(-3\sqrt{2}) \\&= 2-6\sqrt{2}+3\sqrt{2}-9(2) \\&= 2-6\sqrt{2}+3\sqrt{2}-18 \\&= (2-18)+(-6\sqrt{2}+3\sqrt{2}) \\&= -16-3\sqrt{2} .\end{align*} Hence, the product of the given expression is $ -16-3\sqrt{2} $.
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