## Algebra 2 Common Core

$7\sqrt{3}$
Simplify each radical to have $5\sqrt3+\sqrt{4(3)} \text{ and} \\5\sqrt{3} + 2\sqrt{3}.$ RECALL: $ac+bc=(a+b)c$ Combine like terms using the rule above to have: $=(5+2)\sqrt{3} \\=7\sqrt{3}.$