Algebra 2 Common Core

Published by Prentice Hall

Chapter 6 - Radical Functions and Rational Exponents - 6-3 Binomial Radical Expressions - Lesson Check - Page 378: 4

Answer

$7\sqrt{3}$

Work Step by Step

Simplify each radical to have $5\sqrt3+\sqrt{4(3)} \text{ and} \\5\sqrt{3} + 2\sqrt{3}.$ RECALL: $ac+bc=(a+b)c$ Combine like terms using the rule above to have: $=(5+2)\sqrt{3} \\=7\sqrt{3}.$

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