Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-3 Binomial Radical Expressions - Lesson Check - Page 378: 5

Answer

$13$

Work Step by Step

Using the product of the sum and difference of like terms which is given by $(a+b)(a-b)=a^2-b^2,$ the given expression, $ (4+\sqrt{3})(4-\sqrt{3}) ,$ is equivalent to \begin{align*} & (4+\sqrt{3})(4-\sqrt{3}) \\&= (4)^2-(\sqrt{3})^2 \\&= 16-3 \\&= 13 .\end{align*} Hence, the given expression simplifies to $ 13 $.
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