Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-3 Binomial Radical Expressions - Lesson Check - Page 378: 6

Answer

$75+34\sqrt{5}$

Work Step by Step

Using the FOIL Method which is given by $(a+b)(c+d)=ac+ad+bc+bd,$ the given expression, $ (5+2\sqrt{5})(7+4\sqrt{5}) ,$ is equivalent to \begin{align*} & 5(7)+5(4\sqrt{5})+2\sqrt{5}(7)+2\sqrt{5}(4\sqrt{5}) \\&= 35+20\sqrt{5}+14\sqrt{5}+8(5) \\&= 35+20\sqrt{5}+14\sqrt{5}+40 \\&= (35+40)+(20\sqrt{5}+14\sqrt{5}) \\&= 75+34\sqrt{5} .\end{align*} Hence, the product of the given expression is $ 75+34\sqrt{5} $.
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