Answer
$\dfrac{2\sqrt[3]{25x}}{x}$
Work Step by Step
Multiplying the numerator and the denominator by an expression equal to $1$ which will make the denominator a perfect power of the index, the given expression is equivalent to
\begin{align*}\require{cancel}
&
=\dfrac{10}{\sqrt[3]{5x^2}}\cdot\dfrac{\sqrt[3]{5^2x}}{\sqrt[3]{5^2x}}
\\\\&=
\dfrac{10\sqrt[3]{5^2x}}{\sqrt[3]{5^3x^3}}
\\\\&=
\dfrac{10\sqrt[3]{25x}}{\sqrt[3]{(5x)^3}}
\\\\&=
\dfrac{10\sqrt[3]{25x}}{5x}
\\\\&=
\dfrac{\cancel{10}^2\sqrt[3]{25x}}{\cancel5^1x}
\\\\&=
\dfrac{2\sqrt[3]{25x}}{x}
.\end{align*}
Hence, the simplified form of the given expression is $
\dfrac{2\sqrt[3]{25x}}{x}
$.
