Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-2 Multiplying and Dividing Radical Expressions - Practice and Problem-Solving Exercises - Page 372: 57

Answer

$5\sqrt{10}$

Work Step by Step

We are asked to simplify: $\sqrt{5}*\sqrt{50}$ Recall the property (pg. 367): $\sqrt[n]{a}*\sqrt[n]{b}=\sqrt[n]{ab}$ (if $\sqrt[n]{a}$ and $\sqrt[n]{b}$ are real numbers) Applying this property, we get: $\sqrt{5}*\sqrt{50}$ $=\sqrt{5*50}$ $=\sqrt{250}$ $=\sqrt{25*10}$ Using the property again, we have: $=\sqrt{25}\sqrt{10}$ $=5\sqrt{10}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.