Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-2 Multiplying and Dividing Radical Expressions - Practice and Problem-Solving Exercises - Page 372: 58

Answer

$4\sqrt[3]{5}$

Work Step by Step

Extracting the factors that are perfect powers of the index, the given expression, $ \sqrt[3]{4}\cdot\sqrt[3]{80} ,$ is equivalent to \begin{align*}\require{cancel} & =\sqrt[3]{4}\cdot\sqrt[3]{8\cdot10} \\\\&= \sqrt[3]{4}\cdot\sqrt[3]{(2)^3\cdot10} \\\\&= \sqrt[3]{4}\cdot2\sqrt[3]{10} .\end{align*} Using $\sqrt[n]{x}\cdot\sqrt[n]{y}=\sqrt{xy},$ the expression above is equivalent to \begin{align*} & =2\sqrt[3]{4(10)} \\\\&= 2\sqrt[3]{40} .\end{align*} Extracting the factors that are perfect powers of the index, the expression above is equivalent to \begin{align*}\require{cancel} & =2\sqrt[3]{8\cdot5} \\\\&= 2\sqrt[3]{(2)^3\cdot5} \\\\&= 2(2)\sqrt[3]{5} \\\\&= 4\sqrt[3]{5} .\end{align*} Hence, the simplified form of the given expression is $ 4\sqrt[3]{5} $.
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